62x^(2/3)-75x^(1/3)-23=0

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Solution for 62x^(2/3)-75x^(1/3)-23=0 equation:


x in (-oo:+oo)

62*x^(2/3)-(75*x^(1/3))-23 = 0

62*x^(2/3)-75*x^(1/3)-23 = 0

t_1 = x^(1/3)

62*t_1^2-75*t_1^1-23 = 0

62*t_1^2-75*t_1-23 = 0

DELTA = (-75)^2-(-23*4*62)

DELTA = 11329

DELTA > 0

t_1 = (11329^(1/2)+75)/(2*62) or t_1 = (75-11329^(1/2))/(2*62)

t_1 = (11329^(1/2)+75)/124 or t_1 = (75-11329^(1/2))/124

t_1 = (75-11329^(1/2))/124

x^(1/3)-((75-11329^(1/2))/124) = 0

1*x^(1/3) = (75-11329^(1/2))/124 // : 1

x^(1/3) = (75-11329^(1/2))/124

( (75-11329^(1/2))/124 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = (11329^(1/2)+75)/124

x^(1/3)-((11329^(1/2)+75)/124) = 0

1*x^(1/3) = (11329^(1/2)+75)/124 // : 1

x^(1/3) = (11329^(1/2)+75)/124

x^(1/3) = (11329^(1/2)+75)/124 // ^ 3

x = ((11329^(1/2)+75)^3)/1906624

x = ((11329^(1/2)+75)^3)/1906624

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